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发表于 2020-1-14 05:25:46
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显示全部楼层
BYTE lpBuffer[] = { 0x8B, 0xFF, 0x55, 0x8B, 0xEC };//导致ce无法附加和注入的hook的地方:0x00000000773F9879->_(E9 E2 90 B6 9A)(8B FF 55 8B EC)
DWORD lpBaseAddress = 0x773F9879;
for (int i = 0; i < 5; i++)
{
WriteProcessMemory(hProcess, (LPVOID)lpBaseAddress, &lpBuffer, 1, NULL);
lpBaseAddress++;
}
就是这么简单。。 |
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